Re: Hiding Brands
This WebDNA talk-list message is from 2004
It keeps the original formatting.
numero = 57396
interpreted = N
texte = Donovan Brooke wrote: > Logically, A contains showif like: > [showif _apple_fred_willma_^_ap_] > yes > [/showif] > > should result to "yes" but it doesn't because thats not how the stamenet > works. I understand you fine, but you are missing _my_ point. Let me put quotes around the strings so you can see: The string "_ap_" is not present in the strings "_apple_" or "_fred_" or "_wilma_", so the [showif doesn't fire] The contains operator "^" takes everything to the right /as a string/ and tries to find it, _exactly_ on the left hand side, /as a string/; the underlying C routine is call instr(). The construct we are talking about is an old trick of wrapping an unknown value with known characters, then mashing all possible values together into a single string, seperated by the known character. Only a single match is desired. You can consider this doing a logical OR using string operations. > IMO, it would have been more logical to impliment this "feature" in the "=" scenerio... > [hideif _a_b_c_=_[value]_] > yes > [/hideif] You are missing the point here as well. There is nothing special about the '_' in this case; any character which isn't also present in either the choices or the [value] can be used (as long as that character doesn't have any additional meaning). For that matter, this should also work [hideif 'a'b'c'd'^'[value]'] since in that context, the single quote has no special meaning. Don't try that in an [if] context though. Got it now? John -- John Peacock Director of Information Research and Technology Rowman & Littlefield Publishing Group 4501 Forbes Boulevard Suite H Lanham, MD 20706 301-459-3366 x.5010 fax 301-429-5748 ------------------------------------------------------------- This message is sent to you because you are subscribed to the mailing list
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Donovan Brooke wrote: > Logically, A contains showif like: > [showif _apple_fred_willma_^_ap_] > yes > [/showif] > > should result to "yes" but it doesn't because thats not how the stamenet > works. I understand you fine, but you are missing _my_ point. Let me put quotes around the strings so you can see: The string "_ap_" is not present in the strings "_apple_" or "_fred_" or "_wilma_", so the [showif doesn't fire] The contains operator "^" takes everything to the right /as a string/ and tries to find it, _exactly_ on the left hand side, /as a string/; the underlying C routine is call instr(). The construct we are talking about is an old trick of wrapping an unknown value with known characters, then mashing all possible values together into a single string, seperated by the known character. Only a single match is desired. You can consider this doing a logical OR using string operations. > IMO, it would have been more logical to impliment this "feature" in the "=" scenerio... > [hideif _a_b_c_=_[value]_] > yes > [/hideif] You are missing the point here as well. There is nothing special about the '_' in this case; any character which isn't also present in either the choices or the [value] can be used (as long as that character doesn't have any additional meaning). For that matter, this should also work [hideif 'a'b'c'd'^'[value]'] since in that context, the single quote has no special meaning. Don't try that in an [if] context though. Got it now? John -- John Peacock Director of Information Research and Technology Rowman & Littlefield Publishing Group 4501 Forbes Boulevard Suite H Lanham, MD 20706 301-459-3366 x.5010 fax 301-429-5748 ------------------------------------------------------------- This message is sent to you because you are subscribed to the mailing list . To unsubscribe, E-mail to: To switch to the DIGEST mode, E-mail to Web Archive of this list is at: http://webdna.smithmicro.com/
John Peacock
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